prove that, in a right angled triangle, the square of the hypotenuse is equal to the sum of
the squares of remaining two sides
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There are many methods.
Use the simplest methof, the square method. Join each pair of adjacent edges to form seperate squares with the side length equal to the length of the corresponding vertices of the triangle.
Now prove.
Hope this helps....☝☝☝
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2
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Check your answer please
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