Prove that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.
Using the above, solve the following:
A ladder reaches a window which is 12m above the ground on one side of the street Keeping its foot at the same point, the ladder is turned to the other side of the street to reach a window 9m high. Find the width of the street if the length of the ladder is 15m.
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refer to diagram
CA = 12 m
DB = 9 m
AB = ?
ladder ht. same in both case = 15 m
in Δ APC by Pythagoras theorem
CA² + AP² = CP² ⇒ CA² = 225 - 144 = 81 ⇒ CA = 9 m
similarly in ΔBPD
DB² + BP² = DP² ⇒ BP² = 225-81 = 144 ⇒ BP = 12m
width of street AB = AP+BP = 12+9= 21m
that's it
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the width of the street is 21m.
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