Prove that in a triangle if measurement of two angles are equal then the length of opposite to these angles are equal.
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Given :
A △ABC in which ∠B=∠C.
To prove :
AB=AC
Construction :
Draw the bisector of ∠A and let it meet BC at D.
Proof :
In △s ABD and ACD,
∠B=∠C
∠BAD=∠CAD
AD=AD
So, by AAS criterion of congruence,
△ABD≅△ACD
⟹AB=AC
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