Prove that in a triangle
the sum of altitudes is less than the
sum of sides of a triangle
Answers
Answered by
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Here's your answer..
______________________
Solution:-
Let AD ,CF and BE the altitude of the triangle.
Since we know that,
Line segment drawn from a point outside a line to line,the Perpendicular is shortest.
So,
=>AD<AC , BE<BC , CF <AB
=>AD+BE+CF < AC +BC +AB
Hence,it is proved that sum of three altitudes of the triangle is less than sides of triangle.
_______________________
#See the attached also..
Hope it helps you...
______________________
Solution:-
Let AD ,CF and BE the altitude of the triangle.
Since we know that,
Line segment drawn from a point outside a line to line,the Perpendicular is shortest.
So,
=>AD<AC , BE<BC , CF <AB
=>AD+BE+CF < AC +BC +AB
Hence,it is proved that sum of three altitudes of the triangle is less than sides of triangle.
_______________________
#See the attached also..
Hope it helps you...
Attachments:
shaams2004:
thank u
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