Question

Prove that in △ABC external bisector of angle A, external bisector of angle B and

internal bisector of angle C are concurrent. plz solve​

Answer 1

Answer:

ANSWER

In △ABC,AE is the external bisector of ∠A meeting BC produced at E.

Let CE=x cm. Now, by the angle bisector theorem, we have

CE

BE

=

AC

AB

⇒

x

12+x

=

6

10

⇒3(12+x)=5x.

⇒x=18.

Hence, CE=18 cm.

solution

Step-by-step explanation:

please mark me brain list