Question

prove that in an isosceles triangle the angles opposite the equal sides are equal

Answer 1

Hey there !

Here is your answer -

Consider the given Isosceles triangle ABC

Given - AB = AC

Construction - Draw AD perpendicular bisector.

To prove - Angle B = Angle C


Proof -

In ∆ABD and ∆ACD

AB = AC - Given

Angle ADB = Angle ADC. - Each 90° (as per the construction)

AD = AD. - Common side

Therefore, ∆ABD congruent ∆ACD

so, Angle B = Angle C. - CPCT



Hence proved !

Answer 2

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