Math, asked by yogeshwarmandal754, 2 months ago

prove that in an isosceles triangles the Angel opposite to equal side​

Answers

Answered by Tusharking2313
1

Step-by-step explanation:

Take a triangle ABC, in which AB=AC. Construct AP bisector of angle A meeting BC at P. Hence proved that angles opposite to equal sides of a triangle are equal.

Answered by vamsi4662
1

Answer:

Take a triangle ABC, in which AB=AC.

Construct AP bisector of angle A meeting BC at P.

In ∆ABP and ∆ACP

AP=AP[common]

AB=AC[given]

angle BAP=angle CAP[by construction]

Therefore, ∆ABP congurent ∆ACP[S.A.S]

This implies, angle ABP=angleACP[C.P.C.T]

Hence proved that angles opposite to equal sides of a triangle are equal.

Step-by-step explanation:

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