prove that in an isosceles triangles the Angel opposite to equal side
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Step-by-step explanation:
Take a triangle ABC, in which AB=AC. Construct AP bisector of angle A meeting BC at P. Hence proved that angles opposite to equal sides of a triangle are equal.
Answered by
1
Answer:
Take a triangle ABC, in which AB=AC.
Construct AP bisector of angle A meeting BC at P.
In ∆ABP and ∆ACP
AP=AP[common]
AB=AC[given]
angle BAP=angle CAP[by construction]
Therefore, ∆ABP congurent ∆ACP[S.A.S]
This implies, angle ABP=angleACP[C.P.C.T]
Hence proved that angles opposite to equal sides of a triangle are equal.
Step-by-step explanation:
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