prove that in any triangle the outer angle at a vertex is equal to the sum of the inner angles at the other two vertices
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Step-by-step explanation:
To prove: angleB + angleC = angleE
let the triangle be ABC.Then,produce side CA to D such that
angleA + angleE = 180 (by linear pair)
angleA = 180 - angleE_____1
we know that sum of all angles is a triangle is 180.then,
angleA + angleB + angleC=180
angleB + angleC = 180 - angleA ____2
put the value of angleA in 2, we get:
angleB + angleC = 180 - ( 180 - angleE)
angleB + angleC = 180 - 180 + angleE
angleB + angleC = angleE
Hence proved
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