prove that in any triangle the outer angle at a vertex is equal to the sum of the inner angles at the other two vertices
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"An exterior ∠ is equal to the addition of the two Δ angles not right next to it.
140º = 60º + 80º; 120º = 80º + 40º;
100º = 60º + 40º
The exterior angle is supplementary to its adjacent Δ angle. 140º is supp to 40º
The 2 exterior angles at each vertex are = in measure because they are vertical angles.
The exterior angles (taken one at a vertex) always total 360º
"
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