Question

prove that in parallelogram the angle bisect of two adjacent angle intersect at Right angle​

Answer 1

Answer:

let the parallelogram be ABCD

so

angA is adjacent to angB

according to the theorem of parallelogram

sum of adjacent angles is always 180

so angA + angB = 180

so 1/2angA + 1/2angB = 90

AO and BO are ang bisector of angA and angB respectively

so ang AOB = 90