prove that in rectangle the Sum of all side greater than twice of a sum of diagonal
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Answer:
AB + BC > AC
BC + CD > BD
CD + AD > AC
AD + AB > BD
(AB + BC + BC + CD + CD + AD + AD + AB) > (AC + BD + AC + BD)
2(AB + BC + CD + AD) > 2(AC + BD + AC + BD)
(AB + BC + CD + AD) > (AC + BD)
Hence proved
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