Question

prove that in triangle cosec(P+R)/2=secQ/2?​

Answer 1

In a triangle PQR,

P+Q+R= 180

Thus

P+R = 180-Q

P+R/2 = 90-Q/2

Thus

cosec(P+R/2) = cosec(90-[90-Q/2])

= sec (Q/2)

Hence proved.

Answer 2

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