Math, asked by Anonymous, 9 months ago

prove that in two concentric circles, the chord of the larger circle, which touches the smaller circle, is bisected at the point of contact.​

Answers

Answered by bannajoby15
0

Step-by-step explanation:

Given: 2 concentric circles be C1 and C2 with centre O

AB be chord of the larger circle C1 which touches the smaller circle C2 at point P.

To Prove: Chord AB is bisected at point of contact i.e., AB=AP

Solution: since AB is a tangent to smaller circle C2

OP perpendicular to AB

Now,

AB is a chord of bigger circle C1 and OP perpendicular to AB

As perpendicular from the centre bisects the chord

Therefore OP would be bisector of chord AB

=>AP=BP

Hence Proved

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