Question

prove that in two concentric circles the chord of the larger circle which touches the smaller circle is bisected at the point of contact

Answer 1

In ∆s OMP and OMQ
OP=OQ(radii of same larger circle)
OM=OM(common)
ANGLE OMP=ANGLE OMQ(radius is perpendicular with tangent)
By RHS, both ∆s are congruent.
PM=QM(by cpct)
Hence proved.
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Answer 2

here is your answer...

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