Question

Prove that in uniform accelerated motion, average velocity is equal to
( u + v / 2 ).​

Answer 1

Answer:

v(avg) = (v + u)/2

Explanation:

v^2 - u^2 = 2as

s = (v^2 - u^2) /2a

and v = u + at

a = (v -u)/t

now v(avg) = total dist/total time

i.e, v(avg) = s/t

v(avg) = (v^2 - u^2) /2a(t)

v(avg) = (v+u)(v-u)/2(v-u)(t)/t

v(avg) = (v + u)/2

hence proved

Answer 2

Answer:

Explanation:

say the object is moving with velocity u for time t.

then it moves with velocity v for time t .

Now total distance is ut+vt

time taken is 2t

so average velocity is (ut+vt)/2t = u+v/2