prove that intersept theorm
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Statement: If there are three or more parallel lines and the intercepts made by them on one transversal are equal, the corresponding intercepts of any transversal are also equal.
Given: l||m||n
P is a transversal intersecting l, m and n at A, B and C respectively such that AB=BC.
Q is another transversal drawn to cut l, m and n at D, E and F respectively. DE and EF are the intercepts made on q.
To prove: DE = EF
Construction: Draw a line through E parallel to p intersecting l in G, n in H respectively.
Proof: AG||BE (given) GE||AB (by construction) AGEB is a parallelogram
From (i) and (ii), GE=EH
Now compare triangles GED and EFH,
GE=EH (proved)
Hence the theorem is proved.
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