Prove that is √2-3√5
is an
irrational number..
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Answer:
let suppose √2-3√5 is a rational no.
then we can write it as
√2-3√5=p/q
q not equal to 0
p and q are co prime integers
√2 = p/q + 3√5
√2 = p+ 3√5/q
here we see that p+3√5/q are all integers
so p+3√5 is rational
so we say that √2 is also rational
but we know that √2 is an irrational number
so there is a contradiction
our assumption is wrong
hence √2-3√5 is irrational number
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