Math, asked by mananpress1224, 10 months ago

prove that is an irrational number...................... a) root 3

Answers

Answered by kparulparekh
0

Step-by-step explanation:

Ur last statement should be that

So we conclude that root3 is irrational.

Hope u got.

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Answered by shivampandit88
0

Answer:

let us assume that √3 is a rational number

Now, let √3 =a/b. where a and b are co prime

b not equal to 0√3= a/b

square both the sides

(√3)^2 =(a/b)^2 3=a^2/b^2

b^2×3=a^2

a^2 is divisible by 3 do a is also divisible by 3

let a=3m for some integers m

(√3)^2 = A/ b^2

3= 9m/b^2

b^2= 9m/3

b^2 =3m

m= 3/b^2

b^2 is divisible by 3 do b is also divisible by 3

a and b both divisible by √3 but co prime number doesn't divisible by both number

so ,this is not a rational number

This is a irrational number

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