prove that is an irrational number...................... a) root 3
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Step-by-step explanation:
Ur last statement should be that
So we conclude that root3 is irrational.
Hope u got.
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Answer:
let us assume that √3 is a rational number
Now, let √3 =a/b. where a and b are co prime
b not equal to 0√3= a/b
square both the sides
(√3)^2 =(a/b)^2 3=a^2/b^2
b^2×3=a^2
a^2 is divisible by 3 do a is also divisible by 3
let a=3m for some integers m
(√3)^2 = A/ b^2
3= 9m/b^2
b^2= 9m/3
b^2 =3m
m= 3/b^2
b^2 is divisible by 3 do b is also divisible by 3
a and b both divisible by √3 but co prime number doesn't divisible by both number
so ,this is not a rational number
This is a irrational number
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