Question

Prove that √з is irrational
​

Answer 1

Answer:

Step-by-step explanation:

Solution:

If possible , let

3

​

be a rational number and its simplest form be

b

a

​

then, a and b are integers having no common factor

other than 1 and b



​

=0.

Now,

3

​

=

b

a

​

⟹3=

b

2

a

2

​

(On squaring both sides )

or, 3b

2

=a

2

.......(i)

⟹3 divides a

2

(∵3 divides 3b

2

)

⟹3 divides a

Let a=3c for some integer c

Putting a=3c in (i), we get

or, 3b

2

=9c

2

⟹b

2

=3c

2

⟹3 divides b

2

(∵3 divides 3c

2

)

⟹3 divides a

Thus 3 is a common factor of a and b

This contradicts the fact that a and b have no common factor other than 1.

The contradiction arises by assuming

3

​

is a rational.

Hence,

3

​

is irrational.

I HOPE IT HELPS YOU

Answer 2

Answer:

As we know that all prime number are irrational

                                      or

we know that prime number have only two factor

   i.e.       1, and it self

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