Prove that is sin power 6 theta + cos power 6 theta + 3 sin squared theta cos square theta is equal to 1
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(Sin^2)^3+(cos^2)3+3sin^2cos^2=1
(Sin^2+cos^2)(sin^4+cos^4+sin^2+cos^2)+3sin^2cos^2
1×{(sin^2)^2+(cos^2)^2(-sin^2cos^2+3sin^2cos^2)
{(Sin)^2+(cos)^2-sin^2cos^2)+3sin^2cos^2
(Sin^2+cos^2)^2-2sin^2cos^2-sin^2cos^2+3sin^2+cos^2
1=1
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