Question

prove that it is equal to Tan^2A​

Answer 1

Step-by-step explanation:

$\frac{1-2tanO+tan²O}{1-2CotO+Cot²O}$

$=>\frac{1+tan²O-2tanO}{1+Cot²O-2CotO}$

$=>\frac{Sec²O-2tanO}{Cosec²O-2CotO}$

$=>\frac{\frac{1}{Cos²O}-2\frac{SinO}{CosO}} {\frac{1}{Sin²O}-2\frac{CosO}{SinO}}$

$=>\frac{\frac{1-2SinOCosO}{Cos²O}} {\frac{1-2CosOSinO}{Sin²O}}$

$=>\frac{1-2SinOCosO}{Cos²O} × \frac{Sin²O} {1-2SinOCosO}$

$=>\frac{Sin²O}{Cos²O}$

$=>tan²O$

$\star \: Hence \: proff$