Question

prove that it is irrational ​

Answer 1

Explanation: mark as Brainliest

let 3√7 be rational

then 3√7=a/b where a and b are integers

√7 =a/3b

since a and b are Integers therefore a/3b is rational but this contradicts the fact that √7 is irrational

hence 3√7 is irrational

Answer 2

Answer:

to prove 3/√7 is irrational

first rationalise the denominator

3/√7=3*√7/(√7)²

⇒3√7/7

let us assume that 3√7/7 is rational

∴3√7/7=a/b,where a and b are co-primes

√7=7a/3b

7a/3b is a rational number

so √7 is also a rational number

but this contradicts the fact that √7 is irrational.

thois contradiction has arisen because of our wrong assumption that 3/√7 is rational.

∴3/√7 is  irrational

Step-by-step explanation: