Question

prove that it is irrational number 6-√2 . believe me guys it is very important / urgent . provide me step by step . please guys requesting you.​

Answer 1

Answer:

let us assume that 6 - √2 is an rational number

6 -√2=p/q

here p and q are coprime integers and q is not equal to zero

-√2= p/q-6

-√2= p-6/q ....... taking q as LCM

here-√2 is irrational number and p, 6 and q are rational numbers

therefore-√2 =p-6/q is not possible

therefore our assumption is wrong

therefore it is proved that 6 -√2 is a irrational number

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