prove that it was irrational
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Hey!
2) 7√5
Let suppose 7√5 is rational number
7√5= P/q
√5=P/7q
Our contradiction is wrong because Rational can't be equal to irrational.
So 7√5 is irrational
®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®
3. 6+√2
Let suppose 6+√2 be a rational number
P/q =6+√2
Squaring both sides
(P/q)²=(6+√2)²
Now use formula of (a+b)²=a²+2ab+b²
P²/q²=(6)²+2.6.√2+(√2)²
P²/q²=36+12√2+2
P²/q²=38+12√2
P²/q²-38= 12√2
Our contradiction is wrong because Rational can't be equal to irrational.
So 6+√2 is irrational
®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®
Regards :)
Yash Raj ✌
2) 7√5
Let suppose 7√5 is rational number
7√5= P/q
√5=P/7q
Our contradiction is wrong because Rational can't be equal to irrational.
So 7√5 is irrational
®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®
3. 6+√2
Let suppose 6+√2 be a rational number
P/q =6+√2
Squaring both sides
(P/q)²=(6+√2)²
Now use formula of (a+b)²=a²+2ab+b²
P²/q²=(6)²+2.6.√2+(√2)²
P²/q²=36+12√2+2
P²/q²=38+12√2
P²/q²-38= 12√2
Our contradiction is wrong because Rational can't be equal to irrational.
So 6+√2 is irrational
®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®
Regards :)
Yash Raj ✌
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