Question

prove that -


its urgent.
plz..follow me slso
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Answer 1

Answer:

if this answer is right di

then tell me your name di .

in my answer

if wrong then not ...

Answer 2

$\frac{sin \: \alpha }{1 - cos \: \alpha } \\ \\ = (\frac{sin \: \alpha }{1 - cos \: \alpha }) \times (\frac{1 + cos \: \alpha }{1 + cos \: \alpha }) \\ \\ = \frac{sin \: \alpha + sin \: \alpha \: cos \: \alpha }{1 - {cos}^{2} \alpha } \\ \\ = \frac{sin \: \alpha + sin \: \alpha \: cos \: \alpha }{ {sin}^{2} \alpha } \\ \\ = \frac{sin \: \alpha }{ {sin}^{2} \alpha } + \frac{sin \: \alpha \: cos \alpha }{ {sin}^{2} \alpha } \\ \\ = \frac{1}{sin \alpha } + \frac{cos \alpha }{sin \alpha } \\ \\ = cosec \alpha + cot \alpha$