Question

prove that
kinetic energy=1/2 kt

Answer 1

$a = f \div m$
$v { }^{2} = u {}^{2} + 2as$
$v {}^{2} = 0 {}^{2} + 2as$
$2a = s \times v {}^{2}$
$a = \frac{v {}^{2} }{2} \times 5 = \frac{f}{m}$
$\frac{v {}^{2} }{2} = \frac{f}{m } \times s$
$fs = \frac{1}{2} m {v}^{2}$
$w = fs$
$k.e = \frac{1}{2} m {v}^{2}$
hence it is prooved

Answer 2

right answer... given