Prove that length of tangents drawn from an external point to a circle are equal use above theorem find the length of ad be cf
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To prove PT=QT
Proof: Consider the triangle OPT and OQT.
OP=OQ
∠OPT=∠OQT=90∘
OT=OT (common side)
Hence by RHS the triangles are equal.
Hence PT=QT
Hence Proved.
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Answer:
To prove PT=QT
Proof: Consider the triangle OPT and OQT.
OP=OQ
∠OPT=∠OQT=90∘
OT=OT (common side)
Hence by RHS the triangles are equal.
Hence PT=QT
Hence Proved.
Step-by-step explanation:
for diagram http://clay6.com/mpaimg/24d.jpg
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