Question

prove that LHS = RHS

Answer 1

here's the answer........

pls mark brainliest

Answer 2

Answer:

I'm currently brushing up on my math before heading back to school for my bachelor's and am practicing on some questions.

Given the following equation :

x2−3xx2−9=1−3x−9x2−9.

and that I have to prove that the LHS = RHS; How would I go about doing so?

What I've done:

I've simply brought (3x−9)/(x2−9) over to the LHS, resulting in the equation (x2−3x)/(x2−9)+(3x−9)/(x2−9)=1 , which gives me (x2−9)/(x2−9)=1.(LHS = RHS)

However, I do not think that what I've done is the correct method of proving. Should I have instead transformed the LHS into RHS without bringing anything from LHS to RHS and vice versa?

Furthermore , after which I'm integrating (x2−3x)/(x2−9) by doing the following:

What I first did was factorise the denominator into (x+3)(x−3). I then equated (x2−3x)=A(x+3)+B(x−3).

Given that x=3⟹A=0 and given that x=−3⟹B=−3.

This would then give me the following equation to integrate:

[(−3)/(x+3)+0(x−3)]dx

which led me to the answer −3ln|x+3|+C.

However, when I checked my answer, the correct answer should be

x−3ln|x+3|+C.

Where did the missing x come from?

Any assistance would be greatly appreciated

Thanks!

plz mark as brainliest

Step-by-step explanation: