prove that LHS=RHS
and prove the identity
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Answered by
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Answer:
(1+tan^2A) + (1+1/tan^2A) = 1/sin^2A-sin^4A
taking L.H.S
(1+tan^2A) + (1+1/tan^A)
= (1+tan^2A) + (1+cot^2A)
= sec^2A + cosec^2A
= 1/cos^2A + 1/sin^2A
= sin^2A + cos^2A /cos^2A . sin^2A
= 1/(1-sin^2A)*sin^2A (sin^2A+cos^2A=1)
= 1/sin^2A - sin^4A (H. P)
(L.H.S=R.H.S)
I hope this answer helps you.....
Answered by
0
Answer:
Step-by-step explanation:
The answer is here,
Given that,
= > \: \frac{a + ib}{c + id} = p + iq
We can replace the " i " as " -i ".
= > \frac{a - ib}{c - id} = p - iq
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