Question

prove that LHS=RHS
and prove the identity ​

Answer 1

Answer:

(1+tan^2A) + (1+1/tan^2A) = 1/sin^2A-sin^4A

taking L.H.S

(1+tan^2A) + (1+1/tan^A)

= (1+tan^2A) + (1+cot^2A)

= sec^2A + cosec^2A

= 1/cos^2A + 1/sin^2A

= sin^2A + cos^2A /cos^2A . sin^2A

= 1/(1-sin^2A)*sin^2A (sin^2A+cos^2A=1)

= 1/sin^2A - sin^4A (H. P)

(L.H.S=R.H.S)

I hope this answer helps you.....

Answer 2

Answer:

Step-by-step explanation:

The answer is here,

Given that,

= > \: \frac{a + ib}{c + id} = p + iq

We can replace the " i " as " -i ".

= > \frac{a - ib}{c - id} = p - iq