prove that log[1^1/5+32^1/5+243^1/5]=1/5[[log1+log32+log243]
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Answer:Therefore the exponential form is 23=8 and the logarithmic form is log28=3. ... 3− 5=1243. −5=log3(1243). Show Answer. (1,7)3=4,913. 3=log1,7(4,913) ... 25=32.
Answer. log11000=−3. The logarithm of 11000 to base 10 is equal to −3.
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