Question

prove that : Log 10^800 = 2 + 3. Log 10^ 2
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Answer 1

$LHS≠RHS$

Explanation:

$we \: \: know \: \: that \: \: \boxed{log {x}^{n} = nlogx}\\ Now, \: \: LHS = log(10)^{800} \\ = 800 \times log(10) \\ = 800 \times 1 = 800 \\ Now, \: \: RHS = 2 + 3. log(10)^{2} \\ = 2 + 3 \times 2 \times log(10) \\ = 2 + 3 \times 2 \times 1 \\ = 2 + 6 = 8 \\ we \: \: see \: \: that \: \: LHS≠RHS$