Prove that log 12=log 3+log 4
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We have 12=3x4
Apply log on both sides
Log12=log(3x4)
Log12=log3+log4
Thus,log12=log3+log4
[.logmn=logm+logn]
Apply log on both sides
Log12=log(3x4)
Log12=log3+log4
Thus,log12=log3+log4
[.logmn=logm+logn]
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