prove that log 32 base 2 is equal to 5 using formula logmn base a is equal to log m base a +logn base s
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2 is equal to 5 equal to log m base a +logn base s
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we know log a base a = 1.
log 32 base 2= log 2 base 2+log 16 base 2
= log2 base 2+ log 2 base 2+log 8 base 2
=log2 base 2+log 2 base 2+log 2 base 2+log 4 base 2
=log 2 base 2+log 2base 2+log2base2+log2bas2+log2base2
=1+1+1+1+1=5
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