Question

prove that log 8+ log 27 + log 125 divided
by 1 + log 3 is equal to 3​

Answer 1

Step-by-step explanation:

$\frac{log(8) + log(27) + log(125)}{1 + log(3) }$

= log 2^3 + log 3^3 + log 5^3/1+log3

= 3 log 2 + 3 log 3 + 3 log 5 / 1+log 3

= 3 (log2+log3+log5) / 1+log3

= 3 ( log 2•3•5) / 1+ log3

= 3 (log 30) / 1+ log3

= 3 ( 1.477) / 1 + 0.477

{ because log3 = 0.477 &

log 30 = 1.477 }

= 3 (1.477) / 1.477

= 3 (1)

=3