Question

Prove that log 9.5= log19-log2

Answer 1

Answer:

Proved.

Step-by-step explanation:

From L.H.S,

$\text{log }9.5=\text{log }(\frac{19}{2})$

We know that,

$\text{log }(\frac{a}{b})=\text{log }a-\text{log }b$

Therefore,

[tex]\text{log }9.5=\text{log }(\frac{19}{2})\\ =\text{log }19-\text{log }2[/tex]

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