Question

Prove that (log a) ^2 - (log b) ^2=log ab+loga/b

Answer 1

Answer:

use a^2 - b^2 is (a+b) (a-b)

Step-by-step explanation:

(log a) ^2 - (log b) ^2 = (log a + log b) (log a - log b)

=log (ab) log(a/b)

I think right side typed wrong