prove that log a+log a²+log a³+...log a⁸=36 log a
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Answered by
0
Step-by-step explanation:
Using product law of logarithms,
Using product law of indices,
I think your question is missing, that's why it couldn't be proved, but I tried. Please mark as brainliest will be highly appreciated :)
Answered by
0
Step-by-step explanation:
log a*a²*a³*...a⁸
= log a^(1+2+3+4+5+6+7+8)
=log a^(8×9/2)= log a³⁶ = 36 loga
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