Question

prove that log a + loga^3+log a^5+ ... + log a^2n-1 = n^2 loga​

Answer 1

Step-by-step explanation:

log a+ log a^3+log a^5+ .....+log a^2ñ-1

=log a+log 3a+log 5a+ ....+(2n-1)log a

=log a{1+3+5+...+(2n-1)}

=log a(n²)

=n^2log a