prove that log a^m=m log a by using logarithm formulas or by some other method...?
Answers
Answered by
1
ok hey buddy here is your answer by UDIT
to prove
log(a^m)=m log(a)
ok taking LHS
we know that log(a×b) =loga+logb........(1)
so log (a^m) = loga×a×a×a.......m terms
=loga+loga+loga+loga...m terms (from 1)
= m loga
hence proved
to prove
log(a^m)=m log(a)
ok taking LHS
we know that log(a×b) =loga+logb........(1)
so log (a^m) = loga×a×a×a.......m terms
=loga+loga+loga+loga...m terms (from 1)
= m loga
hence proved
Similar questions