Question

prove that log a square minus b square is equal to log a b long a / b

Answer 1

Hi ,

LHS = ( log a )² - ( log b )²

= ( log a + log b ) ( log a - log b )

[ Since , x² - y² = ( x + y )( x - y ) ]

= log ( ab ) log ( a/b )

[ Since , i ) log m + log n = log mn

ii ) log m - log n = log ( m/n ) ]

= RHS

I hope this helps you.

: )

Answer 2

Answer:

keep in your mind that x²-y² = (x+y)(x-y) and solve the entire question on this formula!

hope it helps you:-)