Question

prove that log a to the base a is 1

Answer 1

According to given sum,
let,

$log_{a}(a) = x$
${a}^{x} = a$
we can write the equation as

${a}^{x} = {a}^{1}$
so x =1 .

$but \: x = log_{a}(a)$
$hence \: log_{a}(a) = 1$
:-)Hope it helps u.