Prove that :log root 2 ( log root 2 (log 9 root 3 ))
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Answer:
probe karne ka RHS
kahaan hai..
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Answer:Let me see if I guessed correctly what you wrote:
4logx/2x−−√+2log4xx2=3log2xx3⟺2logx/2x+4log4xx=9log2xx⟹
2logxlogx2+4logxlog4x=9logxlog2x
where log above can be at any base you want (though in higher mathematics it is usually taken to be loge)
Now you could assume x≠1 (otherwise the exercise is very boring) and thus divide through the whole last equation by logx , and then use other properties of logarithms, say like logAB=logA+logB , or logAB=logA−logB , etc.
Also make sure you understand and can justify the first steps shown above.
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