Math, asked by likhithascs, 11 months ago

Prove that Log to the basex (bpowx)=x.

Answers

Answered by MaheswariS
0

Answer:

log_x{x^x}=x

Step-by-step explanation:

Prove that log_x{x^x}=x

I have applied following definition to prove this problem

Concept used:

If N=a^x

Then, log_aN=x

Now,

Let y=x^x

\implies\:log_x{y}=x

\implies\:log_x{x^x}=x

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