Question

Prove that Log to the basex (bpowx)=x.

Answer 1

Answer:

$log_x{x^x}=x$

Step-by-step explanation:

Prove that $log_x{x^x}=x$

I have applied following definition to prove this problem

Concept used:

If $N=a^x$

Then, $log_aN=x$

Now,

Let $y=x^x$

$\implies\:log_x{y}=x$

$\implies\:log_x{x^x}=x$