Prove that log xy base a = log x base a + log y base a
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Step-by-step explanation:
OK,
let,
Log(xy)=logx+logy
suppose a is e as base. as natural log
then, first logx=p
then e^p=x
then also similiarly
logy=q
e^q=y
then xy= e^p+q
log on both sides
logxy=p+q
then put, p and q values
logxy=logx+logy
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