Math, asked by crazyslayer61, 8 months ago

prove that-log10 a2/bc +log10 b2/ca+log 10 c2/ab=0

Answers

Answered by PrithwiCC

2

Answer:

All in log base 10

So, the given expression can be rearranged as:

log (a2/bc × b2/ca × c2/ab)

= log (a2b2c2/a2b2c2)

= log 1

= log 10^0 = 0× log 10 = 0

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