Question

prove that-log10 a2/bc +log10 b2/ca+log 10 c2/ab=0 ​

Answer 1

Answer:

All in log base 10

So, the given expression can be rearranged as:

log (a2/bc × b2/ca × c2/ab)

= log (a2b2c2/a2b2c2)

= log 1

= log 10^0 = 0× log 10 = 0