Question

Prove that log2 (1/320) + 1/(log10 2) + 5 = 0​

Answer 1

Answer:

PROVED

Step-by-step explanation:

$log_{2}( \frac{1}{320} ) + \frac{1}{ log_{10}(2) } + 5 \\ = log_{2}( \frac{1}{ {2}^{5} } \times \frac{1}{10} ) + log_{2}(10) + 5 \\ = log_{2}( {2}^{ - 5} ) - log_{2}(10) + log_{2}(10) + 5 \\ = - 5 + 5 \\ = 0$

IDENTITY USED:

1/[log_a(b)] = log_b(a)

log_a(b×c) = log_a(b) + log_a(c)

log_a(bⁿ) = nlog_a(b)

HOPE IT HELPS :D

Answer 2

Answer:

I don't understand last 3 steps