Question

Prove that log72=3log2+2log3​

Answer 1

$\large\mathcal{\red {\underline {\overline {\mid {\purple {Answer}}\mid}}}}$

$log(72) \\ log(8 \times 9 ) \\ log(8) + log(9) \\ 3 log(2) + 2 log(3)$

Answer 2

Log 72 = Log ( 9x8 )
= Log9 + Log8 [log(mn) = logm+logn]
= Log3^2 + Log 2^3
= 2.Log3 + 3.Log2 [logm^n = n.logm]

Hence proved