prove that (loga)²-(logb)²=(logab)(loga/b)
Answers
Answered by
1
Answer:
Step-by-step explanation:
(loga)²-(logb)² = (loga - logb)(loga + logb)
loga + logb = logab
loga - logb = loga/b
Therefore
(loga)²-(logb)²=(logab)(loga/b)
CHEERS MATE
Answered by
0
Answer:
Step-by-step explanation:
Attachments:
Similar questions