Question

prove that:loga^mn=loga^m+loga^n

Answer 1

HELLO DEAR,


Log^mn = log^m + log^n

Let x= log^m = a^x = m

Y = log^n = a^y = n

mn = a^x × a^y = a^(x + y)

=> Log^mn = x + y

=> log^m + log^n

I HOPE ITS HELP YOU DEAR,
THANKS