prove that loga^xy = loga^x + loga^y
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Step-by-step explanation:
Let m = loga x and n = loga y
Step 2: Write in exponent form
x = am and y = an
Step 3: Multiply x and y
x • y = am • an = am+n
Step 4: Take log a of both sides and evaluate
log a xy = log a am+n
log a xy = (m + n) log a a
log a xy = m + n
log a xy = loga x + loga y
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